2/3x+5=3x-3

Solution for 2/3x+5=3x-3 equation:

2/3x+5=3x-3

We move all terms to the left:

2/3x+5-(3x-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

2/3x-3x+3+5=0

We multiply all the terms by the denominator


-3x*3x+3*3x+5*3x+2=0

Wy multiply elements

-9x^2+9x+15x+2=0

We add all the numbers together, and all the variables

-9x^2+24x+2=0

a = -9; b = 24; c = +2;
Δ = b2-4ac
Δ = 242-4·(-9)·2
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-18\sqrt{2}}{2*-9}=\frac{-24-18\sqrt{2}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+18\sqrt{2}}{2*-9}=\frac{-24+18\sqrt{2}}{-18}
$