2/3x+4=5/2x-7

Solution for 2/3x+4=5/2x-7 equation:

2/3x+4=5/2x-7

We move all terms to the left:

2/3x+4-(5/2x-7)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x-7)!=0

x∈R


We get rid of parentheses

2/3x-5/2x+7+4=0

We calculate fractions


4x/6x^2+(-15x)/6x^2+7+4=0

We add all the numbers together, and all the variables

4x/6x^2+(-15x)/6x^2+11=0

We multiply all the terms by the denominator


4x+(-15x)+11*6x^2=0

Wy multiply elements

66x^2+4x+(-15x)=0

We get rid of parentheses

66x^2+4x-15x=0

We add all the numbers together, and all the variables

66x^2-11x=0

a = 66; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·66·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*66}=\frac{0}{132}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*66}=\frac{22}{132}
=1/6
$