2/3x+3x=77

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Solution for 2/3x+3x=77 equation:



2/3x+3x=77
We move all terms to the left:
2/3x+3x-(77)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
3x+2/3x-77=0
We multiply all the terms by the denominator
3x*3x-77*3x+2=0
Wy multiply elements
9x^2-231x+2=0
a = 9; b = -231; c = +2;
Δ = b2-4ac
Δ = -2312-4·9·2
Δ = 53289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{53289}=\sqrt{9*5921}=\sqrt{9}*\sqrt{5921}=3\sqrt{5921}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-231)-3\sqrt{5921}}{2*9}=\frac{231-3\sqrt{5921}}{18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-231)+3\sqrt{5921}}{2*9}=\frac{231+3\sqrt{5921}}{18} $

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