2/3x+20=3/4x=x

Solution for 2/3x+20=3/4x=x equation:

2/3x+20=3/4x=x

We move all terms to the left:

2/3x+20-(3/4x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(+3/4x)+20=0

We get rid of parentheses

2/3x-3/4x+20=0

We calculate fractions


8x/12x^2+(-9x)/12x^2+20=0

We multiply all the terms by the denominator


8x+(-9x)+20*12x^2=0

Wy multiply elements

240x^2+8x+(-9x)=0

We get rid of parentheses

240x^2+8x-9x=0

We add all the numbers together, and all the variables

240x^2-1x=0

a = 240; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·240·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*240}=\frac{0}{480}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*240}=\frac{2}{480}
=1/240
$