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2/3x+2/3=1/5x=2/3x
We move all terms to the left:
2/3x+2/3-(1/5x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x-(+1/5x)+2/3=0
We get rid of parentheses
2/3x-1/5x+2/3=0
We calculate fractions
10x/135x^2+(-27x)/135x^2+10x/135x^2=0
We multiply all the terms by the denominator
10x+(-27x)+10x=0
We add all the numbers together, and all the variables
20x+(-27x)=0
We get rid of parentheses
20x-27x=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0
Równanie nie ma rozwiązania
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