2/3x+1=x+4

Solution for 2/3x+1=x+4 equation:

2/3x+1=x+4

We move all terms to the left:

2/3x+1-(x+4)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

2/3x-x-4+1=0

We multiply all the terms by the denominator


-x*3x-4*3x+1*3x+2=0

Wy multiply elements

-3x^2-12x+3x+2=0

We add all the numbers together, and all the variables

-3x^2-9x+2=0

a = -3; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·(-3)·2
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{105}}{2*-3}=\frac{9-\sqrt{105}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{105}}{2*-3}=\frac{9+\sqrt{105}}{-6}
$