2/3x+1=16-x

Solution for 2/3x+1=16-x equation:

2/3x+1=16-x

We move all terms to the left:

2/3x+1-(16-x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(-1x+16)+1=0

We get rid of parentheses

2/3x+1x-16+1=0

We multiply all the terms by the denominator


1x*3x-16*3x+1*3x+2=0

Wy multiply elements

3x^2-48x+3x+2=0

We add all the numbers together, and all the variables

3x^2-45x+2=0

a = 3; b = -45; c = +2;
Δ = b2-4ac
Δ = -452-4·3·2
Δ = 2001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2001}}{2*3}=\frac{45-\sqrt{2001}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2001}}{2*3}=\frac{45+\sqrt{2001}}{6}
$