2/3x+18=3/4x+10

Solution for 2/3x+18=3/4x+10 equation:

2/3x+18=3/4x+10

We move all terms to the left:

2/3x+18-(3/4x+10)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x+10)!=0

x∈R


We get rid of parentheses

2/3x-3/4x-10+18=0

We calculate fractions


8x/12x^2+(-9x)/12x^2-10+18=0

We add all the numbers together, and all the variables

8x/12x^2+(-9x)/12x^2+8=0

We multiply all the terms by the denominator


8x+(-9x)+8*12x^2=0

Wy multiply elements

96x^2+8x+(-9x)=0

We get rid of parentheses

96x^2+8x-9x=0

We add all the numbers together, and all the variables

96x^2-1x=0

a = 96; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·96·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*96}=\frac{0}{192}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*96}=\frac{2}{192}
=1/96
$