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2/3x+14-3x=-17
We move all terms to the left:
2/3x+14-3x-(-17)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-3x+2/3x+31=0
We multiply all the terms by the denominator
-3x*3x+31*3x+2=0
Wy multiply elements
-9x^2+93x+2=0
a = -9; b = 93; c = +2;
Δ = b2-4ac
Δ = 932-4·(-9)·2
Δ = 8721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8721}=\sqrt{9*969}=\sqrt{9}*\sqrt{969}=3\sqrt{969}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(93)-3\sqrt{969}}{2*-9}=\frac{-93-3\sqrt{969}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(93)+3\sqrt{969}}{2*-9}=\frac{-93+3\sqrt{969}}{-18} $
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