2/3x+1/6=1/2x-5

Solution for 2/3x+1/6=1/2x-5 equation:

2/3x+1/6=1/2x-5

We move all terms to the left:

2/3x+1/6-(1/2x-5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x-5)!=0

x∈R


We get rid of parentheses

2/3x-1/2x+5+1/6=0

We calculate fractions


12x^2/216x^2+144x/216x^2+(-108x)/216x^2+5=0

We multiply all the terms by the denominator


12x^2+144x+(-108x)+5*216x^2=0

Wy multiply elements

12x^2+1080x^2+144x+(-108x)=0

We get rid of parentheses

12x^2+1080x^2+144x-108x=0

We add all the numbers together, and all the variables

1092x^2+36x=0

a = 1092; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·1092·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*1092}=\frac{-72}{2184}
=-3/91
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*1092}=\frac{0}{2184}
=0
$