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2/3x+1/2(4x-12)=10
We move all terms to the left:
2/3x+1/2(4x-12)-(10)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2(4x-12)!=0We calculate fractions
x∈R
(4x4/(6x^24+3x/(6x^24-10=0
We do not support expression: x^24
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