2/3x+(-2)=20

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Solution for 2/3x+(-2)=20 equation: 



2/3x+(-2)=20

We move all terms to the left:

2/3x+(-2)-(20)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



determiningTheFunctionDomain
2/3x-20+(-2)=0

We add all the numbers together, and all the variables

2/3x-22=0

We multiply all the terms by the denominator


-22*3x+2=0

Wy multiply elements

-66x+2=0

We move all terms containing x to the left, all other terms to the right

-66x=-2

x=-2/-66

x=1/33

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