2/3x(x-6)=3/4(x+16)

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Solution for 2/3x(x-6)=3/4(x+16) equation: 



2/3x(x-6)=3/4(x+16)

We move all terms to the left:

2/3x(x-6)-(3/4(x+16))=0



Domain of the equation: 3x(x-6)!=0

x∈R





Domain of the equation: 4(x+16))!=0

x∈R



We calculate fractions


(8xx/(3x(x-6)*4(x+16)))+(-9xx/(3x(x-6)*4(x+16)))=0



We calculate terms in parentheses: +(8xx/(3x(x-6)*4(x+16))), so:

8xx/(3x(x-6)*4(x+16))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)





We calculate terms in parentheses: +(-9xx/(3x(x-6)*4(x+16))), so:

-9xx/(3x(x-6)*4(x+16))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)



We get rid of parentheses

8xx-9xx=0

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