2/3x(6x-9)=1/2(7x+6)

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Solution for 2/3x(6x-9)=1/2(7x+6) equation: 



2/3x(6x-9)=1/2(7x+6)

We move all terms to the left:

2/3x(6x-9)-(1/2(7x+6))=0



Domain of the equation: 3x(6x-9)!=0

x∈R





Domain of the equation: 2(7x+6))!=0

x∈R



We calculate fractions


(4x7/(3x(6x-9)*2(7x+6)))+(-3x6/(3x(6x-9)*2(7x+6)))=0



We calculate terms in parentheses: +(4x7/(3x(6x-9)*2(7x+6))), so:

4x7/(3x(6x-9)*2(7x+6))

We multiply all the terms by the denominator


4x7

We add all the numbers together, and all the variables

4x^7

We do not support expression: x^7

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