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2/3w+3=5/6w-1
We move all terms to the left:
2/3w+3-(5/6w-1)=0
Domain of the equation: 3w!=0
w!=0/3
w!=0
w∈R
Domain of the equation: 6w-1)!=0We get rid of parentheses
w∈R
2/3w-5/6w+1+3=0
We calculate fractions
12w/18w^2+(-15w)/18w^2+1+3=0
We add all the numbers together, and all the variables
12w/18w^2+(-15w)/18w^2+4=0
We multiply all the terms by the denominator
12w+(-15w)+4*18w^2=0
Wy multiply elements
72w^2+12w+(-15w)=0
We get rid of parentheses
72w^2+12w-15w=0
We add all the numbers together, and all the variables
72w^2-3w=0
a = 72; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·72·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*72}=\frac{0}{144} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*72}=\frac{6}{144} =1/24 $
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