2/3t-1/6t=t-13/2=

Solution for 2/3t-1/6t=t-13/2= equation:

2/3t-1/6t=t-13/2=

We move all terms to the left:

2/3t-1/6t-(t-13/2)=0


Domain of the equation: 3t!=0

t!=0/3

t!=0

t∈R



Domain of the equation: 6t!=0

t!=0/6

t!=0

t∈R


We add all the numbers together, and all the variables

2/3t-1/6t-(+t-13/2)=0

We get rid of parentheses

2/3t-1/6t-t+13/2=0

We calculate fractions


1404t^2/72t^2-t+48t/72t^2+(-12t)/72t^2=0

We add all the numbers together, and all the variables

1404t^2/72t^2-1t+48t/72t^2+(-12t)/72t^2=0

We multiply all the terms by the denominator


1404t^2-1t*72t^2+48t+(-12t)=0

We add all the numbers together, and all the variables

1404t^2+48t-1t*72t^2+(-12t)=0

Wy multiply elements

1404t^2-72t^3+48t+(-12t)=0

We get rid of parentheses

1404t^2-72t^3+48t-12t=0

We do not support etpression: t^3