2/3s+9s=27s

Solution for 2/3s+9s=27s equation:

2/3s+9s=27s

We move all terms to the left:

2/3s+9s-(27s)=0


Domain of the equation: 3s!=0

s!=0/3

s!=0

s∈R


We add all the numbers together, and all the variables

-18s+2/3s=0

We multiply all the terms by the denominator


-18s*3s+2=0

Wy multiply elements

-54s^2+2=0

a = -54; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-54)·2
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*-54}=\frac{0-12\sqrt{3}}{-108}
=-\frac{12\sqrt{3}}{-108}
=-\frac{\sqrt{3}}{-9}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*-54}=\frac{0+12\sqrt{3}}{-108}
=\frac{12\sqrt{3}}{-108}
=\frac{\sqrt{3}}{-9}
$