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2/3n-8=n
We move all terms to the left:
2/3n-8-(n)=0
Domain of the equation: 3n!=0We add all the numbers together, and all the variables
n!=0/3
n!=0
n∈R
-1n+2/3n-8=0
We multiply all the terms by the denominator
-1n*3n-8*3n+2=0
Wy multiply elements
-3n^2-24n+2=0
a = -3; b = -24; c = +2;
Δ = b2-4ac
Δ = -242-4·(-3)·2
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-10\sqrt{6}}{2*-3}=\frac{24-10\sqrt{6}}{-6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+10\sqrt{6}}{2*-3}=\frac{24+10\sqrt{6}}{-6} $
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