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2/3n-111.n=12
We move all terms to the left:
2/3n-111.n-(12)=0
Domain of the equation: 3n!=0We add all the numbers together, and all the variables
n!=0/3
n!=0
n∈R
-111n+2/3n-12=0
We multiply all the terms by the denominator
-111n*3n-12*3n+2=0
Wy multiply elements
-333n^2-36n+2=0
a = -333; b = -36; c = +2;
Δ = b2-4ac
Δ = -362-4·(-333)·2
Δ = 3960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3960}=\sqrt{36*110}=\sqrt{36}*\sqrt{110}=6\sqrt{110}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{110}}{2*-333}=\frac{36-6\sqrt{110}}{-666} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{110}}{2*-333}=\frac{36+6\sqrt{110}}{-666} $
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