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2/3n+9=n-6
We move all terms to the left:
2/3n+9-(n-6)=0
Domain of the equation: 3n!=0We get rid of parentheses
n!=0/3
n!=0
n∈R
2/3n-n+6+9=0
We multiply all the terms by the denominator
-n*3n+6*3n+9*3n+2=0
Wy multiply elements
-3n^2+18n+27n+2=0
We add all the numbers together, and all the variables
-3n^2+45n+2=0
a = -3; b = 45; c = +2;
Δ = b2-4ac
Δ = 452-4·(-3)·2
Δ = 2049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2049}}{2*-3}=\frac{-45-\sqrt{2049}}{-6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2049}}{2*-3}=\frac{-45+\sqrt{2049}}{-6} $
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