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2/3m-3/2m=1/12
We move all terms to the left:
2/3m-3/2m-(1/12)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
2/3m-3/2m-(+1/12)=0
We get rid of parentheses
2/3m-3/2m-1/12=0
We calculate fractions
(-12m^2)/72m^2+48m/72m^2+(-108m)/72m^2=0
We multiply all the terms by the denominator
(-12m^2)+48m+(-108m)=0
We get rid of parentheses
-12m^2+48m-108m=0
We add all the numbers together, and all the variables
-12m^2-60m=0
a = -12; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·(-12)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*-12}=\frac{0}{-24} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*-12}=\frac{120}{-24} =-5 $
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