2/3m+4=20

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Solution for 2/3m+4=20 equation: 



2/3m+4=20

We move all terms to the left:

2/3m+4-(20)=0



Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



We add all the numbers together, and all the variables

2/3m-16=0

We multiply all the terms by the denominator


-16*3m+2=0

Wy multiply elements

-48m+2=0

We move all terms containing m to the left, all other terms to the right

-48m=-2

m=-2/-48

m=1/24

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