2/3d+19=35

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Solution for 2/3d+19=35 equation: 



2/3d+19=35

We move all terms to the left:

2/3d+19-(35)=0



Domain of the equation: 3d!=0

d!=0/3

d!=0

d∈R



We add all the numbers together, and all the variables

2/3d-16=0

We multiply all the terms by the denominator


-16*3d+2=0

Wy multiply elements

-48d+2=0

We move all terms containing d to the left, all other terms to the right

-48d=-2

d=-2/-48

d=1/24

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