2/3c-3+5/4=-c+5/2c+2

Solution for 2/3c-3+5/4=-c+5/2c+2 equation:

2/3c-3+5/4=-c+5/2c+2

We move all terms to the left:

2/3c-3+5/4-(-c+5/2c+2)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 2c+2)!=0

c∈R


We add all the numbers together, and all the variables

2/3c-(-1c+5/2c+2)-3+5/4=0

We get rid of parentheses

2/3c+1c-5/2c-2-3+5/4=0

We calculate fractions


60c^2/96c^2+1c+64c/96c^2+(-240c)/96c^2-2-3=0

We add all the numbers together, and all the variables

60c^2/96c^2+c+64c/96c^2+(-240c)/96c^2-5=0

We multiply all the terms by the denominator


60c^2+c*96c^2+64c+(-240c)-5*96c^2=0

We add all the numbers together, and all the variables

60c^2+64c+c*96c^2+(-240c)-5*96c^2=0

Wy multiply elements

60c^2+96c^3-480c^2+64c+(-240c)=0

We get rid of parentheses

60c^2+96c^3-480c^2+64c-240c=0

We do not support ecpression: c^3