2/3c+4/5c-6=c+7

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Solution for 2/3c+4/5c-6=c+7 equation: 



2/3c+4/5c-6=c+7

We move all terms to the left:

2/3c+4/5c-6-(c+7)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R





Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We get rid of parentheses

2/3c+4/5c-c-7-6=0

We calculate fractions


-c+10c/15c^2+12c/15c^2-7-6=0

We add all the numbers together, and all the variables

-1c+10c/15c^2+12c/15c^2-13=0

We multiply all the terms by the denominator


-1c*15c^2+10c+12c-13*15c^2=0

We add all the numbers together, and all the variables

22c-1c*15c^2-13*15c^2=0

Wy multiply elements

-15c^3-195c^2+22c=0

We do not support ecpression: c^3

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