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2/3a-1/6a=3
We move all terms to the left:
2/3a-1/6a-(3)=0
Domain of the equation: 3a!=0
a!=0/3
a!=0
a∈R
Domain of the equation: 6a!=0We calculate fractions
a!=0/6
a!=0
a∈R
12a/18a^2+(-3a)/18a^2-3=0
We multiply all the terms by the denominator
12a+(-3a)-3*18a^2=0
Wy multiply elements
-54a^2+12a+(-3a)=0
We get rid of parentheses
-54a^2+12a-3a=0
We add all the numbers together, and all the variables
-54a^2+9a=0
a = -54; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-54)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-54}=\frac{-18}{-108} =1/6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-54}=\frac{0}{-108} =0 $
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