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2/3a+1/a=3
We move all terms to the left:
2/3a+1/a-(3)=0
Domain of the equation: 3a!=0
a!=0/3
a!=0
a∈R
Domain of the equation: a!=0We calculate fractions
a∈R
2a/3a^2+3a/3a^2-3=0
We multiply all the terms by the denominator
2a+3a-3*3a^2=0
We add all the numbers together, and all the variables
5a-3*3a^2=0
Wy multiply elements
-9a^2+5a=0
a = -9; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-9)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-9}=\frac{-10}{-18} =5/9 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-9}=\frac{0}{-18} =0 $
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