2/3=1/9(b-4)

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Solution for 2/3=1/9(b-4) equation: 


b in (-oo:+oo)

2/3 = (1/9)*(b-4) // - (1/9)*(b-4)

2/3-((1/9)*(b-4)) = 0

(-1/9)*(b-4)+2/3 = 0

2/3-1/9*(b-4) = 0

(-1/9*3*(b-4))/3+2/3 = 0

2-1/9*3*(b-4) = 0

10/3-1/3*b = 0

(10/3-1/3*b)/3 = 0

(10/3-1/3*b)/3 = 0 // * 3

10/3-1/3*b = 0

10/3-1/3*b = 0 // - 10/3

-1/3*b = -10/3 // : -1/3

b = -10/3/(-1/3)

b = 10

b = 10

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