2/3-5/x=1/3x

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Solution for 2/3-5/x=1/3x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/3-(5/x) = (1/3)*x // - (1/3)*x

2/3-((1/3)*x)-(5/x) = 0

(-1/3)*x-5*x^-1+2/3 = 0

2/3*x^0-1/3*x^1-5*x^-1 = 0

(2/3*x^1-1/3*x^2-5*x^0)/(x^1) = 0 // * x^2

x^1*(2/3*x^1-1/3*x^2-5*x^0) = 0

x^1

(-1/3)*x^2+(2/3)*x-5 = 0

(-1/3)*x^2+(2/3)*x-5 = 0

DELTA = (2/3)^2-(-5*4*(-1/3))

DELTA = -56/9

DELTA < 0

x in { } 

x belongs to the empty set

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