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2/3+2/3+1/5x=2/3x
We move all terms to the left:
2/3+2/3+1/5x-(2/3x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(+2/3x)+2/3+2/3=0
We get rid of parentheses
1/5x-2/3x+2/3+2/3=0
We calculate fractions
27x/135x^2+(-10x)/135x^2+(10x+2)/135x^2=0
We multiply all the terms by the denominator
27x+(-10x)+(10x+2)=0
We get rid of parentheses
27x-10x+10x+2=0
We add all the numbers together, and all the variables
27x+2=0
We move all terms containing x to the left, all other terms to the right
27x=-2
x=-2/27
x=-2/27
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