2/3(z+13)=22

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Solution for 2/3(z+13)=22 equation: 



2/3(z+13)=22

We move all terms to the left:

2/3(z+13)-(22)=0



Domain of the equation: 3(z+13)!=0

z∈R



We multiply all the terms by the denominator


-22*3(z+13)+2=0

Wy multiply elements

-66z(z+2=0

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