2/3(y-4)=1/3(y-6)

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Solution for 2/3(y-4)=1/3(y-6) equation: 



2/3(y-4)=1/3(y-6)

We move all terms to the left:

2/3(y-4)-(1/3(y-6))=0



Domain of the equation: 3(y-4)!=0

y∈R





Domain of the equation: 3(y-6))!=0

y∈R



We calculate fractions


(6yy/(3(y-4)*3(y-6)))+(-3yy/(3(y-4)*3(y-6)))=0



We calculate terms in parentheses: +(6yy/(3(y-4)*3(y-6))), so:

6yy/(3(y-4)*3(y-6))

We multiply all the terms by the denominator


6yy

Back to the equation:

+(6yy)





We calculate terms in parentheses: +(-3yy/(3(y-4)*3(y-6))), so:

-3yy/(3(y-4)*3(y-6))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)



We get rid of parentheses

6yy-3yy=0

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