If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/3(y+3)=y
We move all terms to the left:
2/3(y+3)-(y)=0
Domain of the equation: 3(y+3)!=0We add all the numbers together, and all the variables
y∈R
-1y+2/3(y+3)=0
We multiply all the terms by the denominator
-1y*3(y+3)+2=0
Wy multiply elements
-3y^2(y+2=0
| 2÷x3-5=21 | | 68=1/4x+40 | | 248+m=72 | | 2x^2+36x-600=0 | | 125=c-68 | | -65=-5+c | | 1/2(8x-14)=31 | | 71/2m=87/8 | | (3x+17)+4(x-3)=180 | | 1/4x+40=T | | 5f2f=1 | | 52=4x+6(2x+30) | | -248y=-108 | | 5=w÷12.5 | | 4x+6(2x+30)=52 | | 5*g=30-6 | | 33x+25=33x+-33 | | 33x+25=33x+33 | | 33x+25=33x+-25 | | 8x+-50-15x+2=19 | | 3(x-1)+4-2x=2 | | 4x1=60 | | d=4.5 | | 13=10+z | | 0=3t^2-26t | | 3(z+5=2z+15+z | | 5(x+2)=3x+8) | | 8p-7p=2 | | 7x+3=4x−9 | | y+y=180-8y | | X+2=2(5x-3) | | 19*(x+3)-3=111 |