2/3(x-5)=1+3/4(2-3x)

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Solution for 2/3(x-5)=1+3/4(2-3x) equation: 



2/3(x-5)=1+3/4(2-3x)

We move all terms to the left:

2/3(x-5)-(1+3/4(2-3x))=0



Domain of the equation: 3(x-5)!=0

x∈R





Domain of the equation: 4(2-3x))!=0

x∈R



We add all the numbers together, and all the variables

2/3(x-5)-(1+3/4(-3x+2))=0

We calculate fractions


(8x(-)/(3(x-5)*4(-3x+2)))+(-9xx/(3(x-5)*4(-3x+2)))=0



We calculate terms in parentheses: +(8x(-)/(3(x-5)*4(-3x+2))), so:

8x(-)/(3(x-5)*4(-3x+2))

We add all the numbers together, and all the variables

8x0/(3(x-5)*4(-3x+2))

We multiply all the terms by the denominator


8x0

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-9xx/(3(x-5)*4(-3x+2))), so:

-9xx/(3(x-5)*4(-3x+2))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)



We get rid of parentheses

8x-9xx=0

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