2/3(x-4)=x+1

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Solution for 2/3(x-4)=x+1 equation: 



2/3(x-4)=x+1

We move all terms to the left:

2/3(x-4)-(x+1)=0



Domain of the equation: 3(x-4)!=0

x∈R



We get rid of parentheses

2/3(x-4)-x-1=0

We multiply all the terms by the denominator


-x*3(x-4)-1*3(x-4)+2=0

Wy multiply elements

-3x^2(x-3x(x+2=0

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