2/3(x-4)=6x+8

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Solution for 2/3(x-4)=6x+8 equation: 



2/3(x-4)=6x+8

We move all terms to the left:

2/3(x-4)-(6x+8)=0



Domain of the equation: 3(x-4)!=0

x∈R



We get rid of parentheses

2/3(x-4)-6x-8=0

We multiply all the terms by the denominator


-6x*3(x-4)-8*3(x-4)+2=0

Wy multiply elements

-18x^2(x-24x(x+2=0

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