2/3(x-3)=-4/5(x+3)

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Solution for 2/3(x-3)=-4/5(x+3) equation: 



2/3(x-3)=-4/5(x+3)

We move all terms to the left:

2/3(x-3)-(-4/5(x+3))=0



Domain of the equation: 3(x-3)!=0

x∈R





Domain of the equation: 5(x+3))!=0

x∈R



We calculate fractions


(10xx/(3(x-3)*5(x+3)))+(-(-12xx)/(3(x-3)*5(x+3)))=0



We calculate terms in parentheses: +(10xx/(3(x-3)*5(x+3))), so:

10xx/(3(x-3)*5(x+3))

We multiply all the terms by the denominator


10xx

Back to the equation:

+(10xx)





We calculate terms in parentheses: +(-(-12xx)/(3(x-3)*5(x+3))), so:

-(-12xx)/(3(x-3)*5(x+3))

We multiply all the terms by the denominator


-(-12xx)

We get rid of parentheses

12xx

Back to the equation:

+(12xx)

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