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2/3(x-2)-1=1/2(x-3)
We move all terms to the left:
2/3(x-2)-1-(1/2(x-3))=0
Domain of the equation: 3(x-2)!=0
x∈R
Domain of the equation: 2(x-3))!=0We calculate fractions
x∈R
(4xx/(3(x-2)*2(x-3)))+(-3xx/(3(x-2)*2(x-3)))-1=0
We calculate terms in parentheses: +(4xx/(3(x-2)*2(x-3))), so:
4xx/(3(x-2)*2(x-3))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-3xx/(3(x-2)*2(x-3))), so:We get rid of parentheses
-3xx/(3(x-2)*2(x-3))
We multiply all the terms by the denominator
-3xx
Back to the equation:
+(-3xx)
4xx-3xx-1=0
We move all terms containing x to the left, all other terms to the right
4xx-3xx=1
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