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2/3(x+4)-3/4=1/2x
We move all terms to the left:
2/3(x+4)-3/4-(1/2x)=0
Domain of the equation: 3(x+4)!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3(x+4)-(+1/2x)-3/4=0
We get rid of parentheses
2/3(x+4)-1/2x-3/4=0
We calculate fractions
(-12xx/(3(x+4)*2x*4)+(-18x^2x/(3(x+4)*2x*4)+64x/(3(x+4)*2x*4)=0
We calculate terms in parentheses: +(-12xx/(3(x+4)*2x*4)+(-18x^2x/(3(x+4)*2x*4)+64x/(3(x+4)*2x*4), so:
-12xx/(3(x+4)*2x*4)+(-18x^2x/(3(x+4)*2x*4)+64x/(3(x+4)*2x*4
We can not solve this equation
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