2/3(x+4)-2/5x=17/6

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Solution for 2/3(x+4)-2/5x=17/6 equation: 



2/3(x+4)-2/5x=17/6

We move all terms to the left:

2/3(x+4)-2/5x-(17/6)=0



Domain of the equation: 3(x+4)!=0

x∈R





Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

2/3(x+4)-2/5x-(+17/6)=0

We get rid of parentheses

2/3(x+4)-2/5x-17/6=0

We calculate fractions


(-36xx/(3(x+4)*5x*6)+(-255x^2x/(3(x+4)*5x*6)+360x/(3(x+4)*5x*6)=0



We calculate terms in parentheses: +(-36xx/(3(x+4)*5x*6)+(-255x^2x/(3(x+4)*5x*6)+360x/(3(x+4)*5x*6), so:

-36xx/(3(x+4)*5x*6)+(-255x^2x/(3(x+4)*5x*6)+360x/(3(x+4)*5x*6

We can not solve this equation

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