2/3(x+2)=5/9(x+4)

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Solution for 2/3(x+2)=5/9(x+4) equation: 



2/3(x+2)=5/9(x+4)

We move all terms to the left:

2/3(x+2)-(5/9(x+4))=0



Domain of the equation: 3(x+2)!=0

x∈R





Domain of the equation: 9(x+4))!=0

x∈R



We calculate fractions


(18xx/(3(x+2)*9(x+4)))+(-15xx/(3(x+2)*9(x+4)))=0



We calculate terms in parentheses: +(18xx/(3(x+2)*9(x+4))), so:

18xx/(3(x+2)*9(x+4))

We multiply all the terms by the denominator


18xx

Back to the equation:

+(18xx)





We calculate terms in parentheses: +(-15xx/(3(x+2)*9(x+4))), so:

-15xx/(3(x+2)*9(x+4))

We multiply all the terms by the denominator


-15xx

Back to the equation:

+(-15xx)



We get rid of parentheses

18xx-15xx=0

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