2/3(x+2)=4/30(2x+1)

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Solution for 2/3(x+2)=4/30(2x+1) equation: 



2/3(x+2)=4/30(2x+1)

We move all terms to the left:

2/3(x+2)-(4/30(2x+1))=0



Domain of the equation: 3(x+2)!=0

x∈R





Domain of the equation: 30(2x+1))!=0

x∈R



We calculate fractions


(60x2/(3(x+2)*30(2x+1)))+(-12xx/(3(x+2)*30(2x+1)))=0



We calculate terms in parentheses: +(60x2/(3(x+2)*30(2x+1))), so:

60x2/(3(x+2)*30(2x+1))

We multiply all the terms by the denominator


60x2

We add all the numbers together, and all the variables

60x^2

Back to the equation:

+(60x^2)





We calculate terms in parentheses: +(-12xx/(3(x+2)*30(2x+1))), so:

-12xx/(3(x+2)*30(2x+1))

We multiply all the terms by the denominator


-12xx

Back to the equation:

+(-12xx)



We get rid of parentheses

60x^2-12xx=0

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