2/3(x+2)=1/6(x+6)

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Solution for 2/3(x+2)=1/6(x+6) equation: 



2/3(x+2)=1/6(x+6)

We move all terms to the left:

2/3(x+2)-(1/6(x+6))=0



Domain of the equation: 3(x+2)!=0

x∈R





Domain of the equation: 6(x+6))!=0

x∈R



We calculate fractions


(12xx/(3(x+2)*6(x+6)))+(-3xx/(3(x+2)*6(x+6)))=0



We calculate terms in parentheses: +(12xx/(3(x+2)*6(x+6))), so:

12xx/(3(x+2)*6(x+6))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)





We calculate terms in parentheses: +(-3xx/(3(x+2)*6(x+6))), so:

-3xx/(3(x+2)*6(x+6))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

12xx-3xx=0

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