2/3(x+1)=1/9(x+4)

Solution for 2/3(x+1)=1/9(x+4) equation:

2/3(x+1)=1/9(x+4)

We move all terms to the left:

2/3(x+1)-(1/9(x+4))=0


Domain of the equation: 3(x+1)!=0

x∈R



Domain of the equation: 9(x+4))!=0

x∈R


We calculate fractions


(18xx/(3(x+1)*9(x+4)))+(-3xx/(3(x+1)*9(x+4)))=0


We calculate terms in parentheses: +(18xx/(3(x+1)*9(x+4))), so:

18xx/(3(x+1)*9(x+4))

We multiply all the terms by the denominator


18xx

Back to the equation:

+(18xx)



We calculate terms in parentheses: +(-3xx/(3(x+1)*9(x+4))), so:

-3xx/(3(x+1)*9(x+4))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

18xx-3xx=0