2/3(x+1)=1/6(x-1)

Solution for 2/3(x+1)=1/6(x-1) equation:

2/3(x+1)=1/6(x-1)

We move all terms to the left:

2/3(x+1)-(1/6(x-1))=0


Domain of the equation: 3(x+1)!=0

x∈R



Domain of the equation: 6(x-1))!=0

x∈R


We calculate fractions


(12xx/(3(x+1)*6(x-1)))+(-3xx/(3(x+1)*6(x-1)))=0


We calculate terms in parentheses: +(12xx/(3(x+1)*6(x-1))), so:

12xx/(3(x+1)*6(x-1))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)



We calculate terms in parentheses: +(-3xx/(3(x+1)*6(x-1))), so:

-3xx/(3(x+1)*6(x-1))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

12xx-3xx=0