2/3(x+1)=1/4(x-6)

Solution for 2/3(x+1)=1/4(x-6) equation:

2/3(x+1)=1/4(x-6)

We move all terms to the left:

2/3(x+1)-(1/4(x-6))=0


Domain of the equation: 3(x+1)!=0

x∈R



Domain of the equation: 4(x-6))!=0

x∈R


We calculate fractions


(8xx/(3(x+1)*4(x-6)))+(-3xx/(3(x+1)*4(x-6)))=0


We calculate terms in parentheses: +(8xx/(3(x+1)*4(x-6))), so:

8xx/(3(x+1)*4(x-6))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)



We calculate terms in parentheses: +(-3xx/(3(x+1)*4(x-6))), so:

-3xx/(3(x+1)*4(x-6))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

8xx-3xx=0