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2/3(t-2)=3/4(t+2)
We move all terms to the left:
2/3(t-2)-(3/4(t+2))=0
Domain of the equation: 3(t-2)!=0
t∈R
Domain of the equation: 4(t+2))!=0We calculate fractions
t∈R
(8tt/(3(t-2)*4(t+2)))+(-9tt/(3(t-2)*4(t+2)))=0
We calculate terms in parentheses: +(8tt/(3(t-2)*4(t+2))), so:
8tt/(3(t-2)*4(t+2))
We multiply all the terms by the denominator
8tt
Back to the equation:
+(8tt)
We calculate terms in parentheses: +(-9tt/(3(t-2)*4(t+2))), so:We get rid of parentheses
-9tt/(3(t-2)*4(t+2))
We multiply all the terms by the denominator
-9tt
Back to the equation:
+(-9tt)
8tt-9tt=0
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