2/3(p-12)=-2p-1)+7

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Solution for 2/3(p-12)=-2p-1)+7 equation: 



2/3(p-12)=-2p-1)+7

We move all terms to the left:

2/3(p-12)-(-2p-1)+7)=0



Domain of the equation: 3(p-12)!=0

p∈R



We add all the numbers together, and all the variables

2/3(p-12)-(-2p-1)=0

We get rid of parentheses

2/3(p-12)+2p+1=0

We multiply all the terms by the denominator


2p*3(p-12)+1*3(p-12)+2=0

Wy multiply elements

6p^2(p+3p(p+2=0

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