2/3(p+2)=7/9(p-3)

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Solution for 2/3(p+2)=7/9(p-3) equation: 



2/3(p+2)=7/9(p-3)

We move all terms to the left:

2/3(p+2)-(7/9(p-3))=0



Domain of the equation: 3(p+2)!=0

p∈R





Domain of the equation: 9(p-3))!=0

p∈R



We calculate fractions


(18pp/(3(p+2)*9(p-3)))+(-21pp/(3(p+2)*9(p-3)))=0



We calculate terms in parentheses: +(18pp/(3(p+2)*9(p-3))), so:

18pp/(3(p+2)*9(p-3))

We multiply all the terms by the denominator


18pp

Back to the equation:

+(18pp)





We calculate terms in parentheses: +(-21pp/(3(p+2)*9(p-3))), so:

-21pp/(3(p+2)*9(p-3))

We multiply all the terms by the denominator


-21pp

Back to the equation:

+(-21pp)



We get rid of parentheses

18pp-21pp=0

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