2/3(n-1)=4+n

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Solution for 2/3(n-1)=4+n equation: 



2/3(n-1)=4+n

We move all terms to the left:

2/3(n-1)-(4+n)=0



Domain of the equation: 3(n-1)!=0

n∈R



We add all the numbers together, and all the variables

2/3(n-1)-(n+4)=0

We get rid of parentheses

2/3(n-1)-n-4=0

We multiply all the terms by the denominator


-n*3(n-1)-4*3(n-1)+2=0

Wy multiply elements

-3n^2(n-12n(n+2=0

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